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=90R-0.05R^2
We move all terms to the left:
-(90R-0.05R^2)=0
We get rid of parentheses
0.05R^2-90R=0
a = 0.05; b = -90; c = 0;
Δ = b2-4ac
Δ = -902-4·0.05·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-90}{2*0.05}=\frac{0}{0.1} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+90}{2*0.05}=\frac{180}{0.1} =1800 $
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